[torqueusers] how -l procs works
Ken Nielson
knielson at adaptivecomputing.com
Wed Jun 2 09:04:42 MDT 2010
Hi all,
On another thread with the subject "qsub on several nodes" it was
suggested the procs is a better solution to scattering jobs across all
available processors than nodes. However, I find the procs resource
does not seem to behave the way described in the thread.
For instance if I do the following:
qsub -l procs=5 <job.sh>
The qstat output shows the following resource list
Resource_List.neednodes = 1
Resource_List.nodect = 1
Resource_List.nodes = 1
Resource_List.procs = 5
If I do a qrun on this job it will be assigned a single node and one
processor.
The qstat -f after the job is started gives and exec_host of node/0.
TORQUE ignores the procs keyword and assigns the default of 1 node and
one processor to the job.
Moab interprets procs to mean number of processors requested on a single
node for the job. If I let Moab Schedule the job the exec_host from
qstat is node/0+node/1+node/2+node/3+node/4.
If I make the value of procs greater than the number of processors on
any node moab will not run the job.
Ken
More information about the torqueusers
mailing list